<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Hello! For ease of calculations, we can identify the time it took for the weight to bounce back to the other direction, then the other, and then back to its original position by looking at the time it took for the weight to change from 0 to 25 to 0 to -25 then back to 0. This is one whole cycle of the weight.
By the time the weight first reached zero, 1.5 seconds has passed. By the third time it got to zero again, 7.5 seconds has passed. Therefore, one whole cycle of the weight is 7.5-1.5 = 6.0 seconds.
ANSWER: One whole cycle of the weight took 6 seconds.
Answer: 5,14 and -2
Step-by-step explanation:
The coefficient is the number next to the variable.
So this case the coefficients are 5,14 and -2
Answer:
wala sa choices ang sagot.
ANS: 128
EXPLANATION
a(9)=14+2(9-1)
a(9)=14+2(8)
a(9)=16(8)
9= 128
yan sagot ko po
Answer:
15 kg
Step-by-step explanation:
Radius of a solid sphere : mass of a solid sphere
3 cm : 9 kg
Find the mass of a sphere of the same material of radius 5 cm
Radius of a solid sphere : mass of a solid sphere
5 cm : x kg
Equate both ratios to find x
3 cm : 9 kg = 5 cm : x kg
3/9 = 5/x
3 * x = 9 * 5
3x = 45
x = 45/3
x = 15 kg
The mass of a sphere of the same material of radius 5 cm is 15 kg
