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galina1969 [7]
3 years ago
6

Giving 20 pts!!

Mathematics
2 answers:
neonofarm [45]3 years ago
5 0

1. Obtuse Angle (see image 1). Obtuse angles are angles that are more than 90° in measurement but less than 180°

2. Right Angle (see image 2). Right angles are angles that have the measurement of 90°, and is formed by an intersection of two perpendicular straight lines.

3. Acute Angle (see image 3). Acute angles are angles that are less than 90° in measurement.

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hope this helps

kvasek [131]3 years ago
4 0
Right ankle is exactly 90 degrees, while obtuse is more than, and acute is less than

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Shelly a 4.2 oz of Trail Mix Marsh Marshall ate 4.25 oz of Trail Mix how much more trail mix did Marshall eat
dimulka [17.4K]

With just some easy subtraction we can see that he ate 0.05 more trail mix than shelly. please mark brainliesy if correct, hope this helps!

8 0
3 years ago
Read 2 more answers
Draw a quadrilateral that does not belong. Then explain why.
KiRa [710]

Step-by-step explanation:

Rhombus since the other 3 have lines that go accross the graph horizontally for 3 squares.

3 0
2 years ago
Solve for all x values
mrs_skeptik [129]

Answer:

2,-2,1,-1. those r ur x values.

8 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation yo
Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
3 years ago
Read 2 more answers
Evaluate the indefinite integral. (Use C for the constant of integration.) <br> ex 5 ex dx.
melisa1 [442]

Answer:

  5 e^{x} +C

where C is constant of integration

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<em>Given f(x) = 5 eˣ</em>

Now integrating with respective to 'x' , we get

                                                      I =  \int\limits {5 e^{x} } \, d x

<em> By using integration formula</em>

                                       \int\limits { e^{x} } \, d x = e^{x} +C

                                     I =  \int\limits {5 e^{x} } \, d x  = 5 e^{x} +C

<em>where C is constant of integration</em>

8 0
3 years ago
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