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natima [27]
3 years ago
13

Why is the percent increase from 45 to 75 not equal to the percent decrease from 75 to 45

Mathematics
1 answer:
barxatty [35]3 years ago
7 0
The increase of 45 to 75 is a positive increase. The decrease from 75 to 45 is a negitive
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Please ASAP answer this question:)
Darina [25.2K]

Answer:

17 in

Step-by-step explanation:

H²= 8²+15²

H²= 64+225

H²=289

H= √289

H= 17

8 0
3 years ago
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1000 at 6% interest for 3 years
viktelen [127]

Answer:

Let's say that I have $1000.00 to invest for 3 years at rate of 6% compound interest.

M = 1000 (1 + 0.06)^3 = $1191.16.

My $1000.00, after 3 years, is worth $1191.16.

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Given the figure below, calculate the area
Aleksandr [31]

Answer:

<em>1+√3</em>

Step-by-step explanation:

Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2 * AC * BD

We need to get AC

AC = AD+DC

Get base AD using SOH CAH TOA

tan 45 = 4/AD

AD = 4/tan45

AD = 4/1

AD = 4

Get DC

tan 30 = 4/DC

DC = 4/tan 30

DC = 4/(1/√3)

DC = 4√3

AC = 4 + 4√3

AC = 4(1+√3)

Get the Area of the triangle

<em>Area = 1/2 * 4 *  4(1+√3)</em>

<em>Area of the triangle = 1+√3</em>

6 0
3 years ago
In a bag of 50 marbles, 20 marbles are blue or pink.
Scorpion4ik [409]

Answer:

40%

Step-by-step explanation:

The ratio is 20:50, we can expand to 40:100, so 40%

8 0
3 years ago
Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

4 0
3 years ago
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