What is the principal square root of 81?
2 answers:
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Answer:
y=11
Step-by-step explanation:
Hi there!
We want to find the equation of the line that passes through the point (-8, 11) and is perpendicular to x=-15
If a line is perpendicular to another line, it means that the slopes of those lines are negative and reciprocal; in other words, the product of the slopes is equal to -1
The line x=-15 has an undefined slope, which we can represent as 1/0, which is also undefined.
To find the slope of the line perpendicular to x=-15, we can use this equation (m is the slope):
in this instance would be 1/0, so we can substitute it into the equation:
Multiply both sides by 0
So the slope of the new line is 0
We can substitute it into the equation y=mx+b, where m is the slope and b is the y intercept:
y=0x+b
Now we need to find b:
Since the equation passes through the point (-8,11), we can use its values to solve for b.
Substitute -8 as x and 11 as y:
11=0(-8)+b
Multiply
11=0+b, or 11=b
So substitute into the equation:
y=0x+11
We can also write the equation as y=11
Hope this helps!