No, the cone and the cylinder can't have congruent heights and bases.
<h3>
is it possible that the two cones have congruent bases and congruent heights?</h3>
The volume of a cylinder of radius R and height H is:
V = pi*R^2*H
And for a cone of radius R and height H is:
V = pi*R^2*H/3
So, for the same dimensions R and H, the cone has 1/3 of the volume of the cylinder.
Here, the cylinder has a volume of 120cm³ and the cone a volume of 360cm³, so the cone has 3 times the volume of the cylinder.
This means that the measures must be different, so the cone and the cylinder can't have congruent heights and bases.
If you want to learn more about volumes:
brainly.com/question/1972490
#SPJ1
If you know the radius of the circle do radius times 2.
Easy!
Wouldn’t it just be
(With your formula of volume/rate=time)
250mL/2 hours=
125mL a hour
2.083(three is repeated)mL a minute
0.03472(two is repeated)mL a second
At least that’s what I think
Answer:
<u><em>Variable terms:</em></u>
x and y
<u><em>Constant terms:</em></u>
7 and -9
<u><em>Coefficient terms:</em></u>
-5.6 and 24
Answer:
4 units
Step-by-step explanation:
3-2=1 unit
7-3=4 units
1*4=4 units
