We have that
<span>35 + 30s - 45t
case A)
</span>7⋅(5+30s−45t)---> 35+210s-315t-----> is not <span>equivalent
case B)
</span>5(7+6s−9t)----> 35+30s-45t------> is equivalent to 35 + 30s - 45t
case C)
(−35−30s+45t)×(−1)----> 35+30s-45t---> is equivalent to 35 + 30s - 45t
case D)
10×(3.5+3s−4.5)----> 35+30s-45----> is not equivalent
case E)
( 35/2 - 15s + 45/2t) ⋅ (-2)--->-35+30s-45t---> is not equivalent
the answer is
<span>B. 5(7+6s−9t)
C. (−35−30s+45t)×(−1)</span>
Answer:
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Step-by-step explanation:
I wold say it is b <span>integers from −3 < y ≤ 3 </span>
You can either multiply both equation by -2 or multiply both equations by 3 because when you multiply -2 you can eliminate x term
1. -2(x) -2(y) = -2(1) -> -2x -2y=-2
So far
-2x-2y=-2
+
2x-3y= -30
(-2x+2x) + (-2y-3y)= -32
0-5y = -32
Y= 32/5
Substitute y with 32/5
X+ 32/5= 1
Minus -32/5 over
X= -27/5
I don’t know why my answer doesn’t match with those answers above. I also checked by calculator. Did you write the question wrong?