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Goshia [24]
3 years ago
14

A company did a quality check on all the packs of roasted almonds it manufactured. Each pack of roasted almonds is targeted to w

eigh 21.25 oz. A pack must weigh within 0.24 oz of the target weight to be accepted. What is the range of rejected masses, x, for the manufactured roasted almonds?
Mathematics
1 answer:
aliina [53]3 years ago
5 0
Can you help me out pls?
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Solve for x. Round your answer to the nearest tenth.
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Answer:

i think 120

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I WILL GIVW CROWN NEEP HELP ASAP
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C. between 5 and 6 days

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A complex number z_1z 1 ​ z, start subscript, 1, end subscript has a magnitude |z_1|=6∣z 1 ​ ∣=6vertical bar, z, start subscript
aliina [53]

Answer:

The answer is "\bold{9.19- 9.19\ i}"

Step-by-step explanation:

When the value of z_1 has the following properties:

\to |z_1| =13

\theta = 315^{\circ} \\\\ = 1.75 \pi\ \ \ \ \ \ \ \ \ \ \ \ \ \  \ _{where} \ \ (\pi = 180^{\circ})

Calculating the value of z_1 :

= 13 \times [ \cos(1.75 \pi ) + i \sin(1.75 \pi) ] \\\\=  13 \times[\cos(1.75 \pi - 2\pi ) + \ i \sin(1.75 \pi - 2\pi )]\\ \\= 13 \times [\cos(-0.25 \pi ) +\  i \sin(-0.25 \pi) ]\\\\= 13 \times [0.707106781 - 0.707106781]\\\\ =9.19 - 9.19\ i \\\\

3 0
3 years ago
A
vredina [299]

Answer:

d is the answer young man

7 0
3 years ago
Find the smallest multiple of 15 such that each digit of the multiple is either 0 or 4
SCORPION-xisa [38]
The answer is 4440.  You can determine this by using your rules of divisibility.  We know that is must end in a 0 or 5 to be divisible by 5 and that the sum of the digits must be divisible by 3 in order to divide by 3. One or two 4's together are not divisible by 3.  Three 4's are, but it must end in 0 to be divisible by 5 as well.


5 0
3 years ago
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