3x+y=17
=> 3x=17-y
Again, x+3y=-1
=> 3y= -1-x
now, 3x+3y= (17-y)+(-1-x)
= 17-y-1-x
= 16-x-y
Answer:
y = -4x - 32
Step-by-step explanation:
First, find the slope using rise over run (y2 - y1) / (x2 - x1)
Plug in the points:
(y2 - y1) / (x2 - x1)
(8 - 4) / (-10 + 9)
4 / -1
= -4
So, the slope is -4. Plug in the slope and a point into y = mx + b, and solve for b:
y = mx + b
4 = -4(-9) + b
4 = 36 + b
-32 = b
Then, plug in the slope and y intercept into y = mx + b
y = -4x - 32 is the equation of the line
Is there options just wondering
When you are given a point (x1,y1) and slope m the equation is
y-y1=m(x-x1)
given
slope=7
(x,y)
(3,22)
x1=3
y1=22
y-22=7(x-3) is the equation or
y=7x+1