All categories

3 years ago

Complete the function table below function f(x) = 6x -3

Mathematics

1 answer:

taurus [48]3 years ago

6 0

When x is equal to -1:
f(-1)=6(-1)-3
=-7-3
=-10
y=-10

When x is equal to 0:
f(0)=6(0)-3
=0-3
=-3
y=-3

When x is equal to 1:
f(1)=6(1)-3
=6-3
=3
y=3

When x is equal to 2:
f(2)=6(2)-3
=12-3
=9
y=9

You might be interested in

the area of a parallelogram is 96 cm squared. The height of the parallelogram is 4 cm less than the length of the base. What is

ohaa [14]

24???????????????????????????????????????????????????????????????????????

6 0

3 years ago

Read 2 more answers

The national debt of the united states is 970 billion dollars. the 1980 census showed 226,504,825 people. about how many dollars

sleet_krkn [62]

970,000,000,000/226,504,825 =
4282.4694794

5 0

3 years ago

What’s the answer to number 1?

Darya [45]

Answer:

increase = New number - original number

inc % = (increase ÷ original number) *100%

Step-by-step explanation:

133 - 76 = 56

inc % = 57 ÷ 76 = 0.75

0.75*100% = 75%

7 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Directed line segment has endpoints P(– 8, – 4) and Q(4, 12). Determine the point that partitions the directed line segment in a

larisa86 [58]

Answer:

Point (1,8)

Step-by-step explanation:

We will use segment formula to find the coordinates of point that will partition our line segment PQ in a ratio 3:1.

When a point divides any segment internally in the ratio m:n, the formula is:

$[x=\frac{mx_2+nx_1}{m+n},y= \frac{my_2+ny_1}{m+n}]$

Let us substitute coordinates of point P and Q as:

$x_1=-8$ ,

$y_1=-4$

$x_2=4$

$y_2=12$

$m=3$

$n=1$

$[x=\frac{(3*4)+(1*-8)}{3+1},y=\frac{(3*12)+(1*-4)}{3+1}]$

$[x=\frac{12-8}{4},y=\frac{36-4}{4}]$

$[x=\frac{4}{4},y=\frac{32}{4}]$

$[x=1,y=8]$

Therefore, point (1,8) will partition the directed line segment PQ in a ratio 3:1.

7 0

3 years ago