Helpp pls ASAP !! :(((

ANSWER QUICK What are the values of a, b, and c in the quadratic equation 0=1/2x^2-3x?

Inga [223]

Answer:

$a=\dfrac{1}{2}\\ \\b=-3\\ \\c=0$

Step-by-step explanation:

The general form of the quadratic equation is

$ax^2+bx+c=0$

You are given the quadratic equation

$0=\dfrac{1}{2}x^2-3x$

It can be rewritten in standard form as

$\dfrac{1}{2}x^2-3x=0$

Hence,

$a=\dfrac{1}{2}\\ \\b=-3\\ \\c=0$

8 0

4 years ago

If x = 6, what is 5x + 6 equal to?

pickupchik [31]

Answer: 5x6=30 30+6=36 answer is 36

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Help please!!!! final exam

LiRa [457]

Answer:

The Rate is 22.5 mph

The distance it traveled was 240 mph

Step-by-step explanation:

6 0

2 years ago

In Exercise,find the horizontal asymptote of the graph of the function. f(x) = x/2x

tester [92]

Answer:

The horizontal asymptote for the function f(x) is 1/2

Step-by-step explanation:

We were given the function

$f(x)=\frac{x}{2x}$

which could be simplified as

$f(x)=\frac{x}{2x}=\frac{1}{2}$

this means that the function is a constant of value 1/2 for all value of x.

Then, in particular, the value of f will be 1/2 for x when x tends to infinite and minus infinite.

And because to find the horizontal asymptote of a function we have to calculate the limit of the function when x tends to infinite or minus infinite, we can ensure that this asymptote has also the value 1/2 of f.

7 0

4 years ago

A 20-ft-long wire is used to support a television antaans. The wire is connected to the

MariettaO [177]

Answer:

The distance of base of wire to the base of tower is 13.27 ft

Step-by-step explanation:

Given as :

The measure of wire connected between base ad antenna top = 20 ft

The wire is connected to the antenna on tower at height h = 15 ft above the ground

Let The distance of base of wire to the base of tower = x ft

Let the angle drawn on ground = Ф

Now, According to question

In figure AOB

Sin angle = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

i.e SinФ = $\dfrac{\textrm AB}{\textrm BO}$

Or, SinФ = $\dfrac{\textrm h}{\textrm 20}$

Or, SinФ = $\dfrac{\textrm 15}{\textrm 20}$

Or, SinФ = $\dfrac{\textrm 3}{\textrm 4}$

or, Ф = $sin^{-1}(\frac{3}{4})$

∴ Ф = 48.5°

Now, Again from figure

Tan angle = $\dfrac{\textrm perpendicular}{\textrm base}$

i.e TanФ = $\dfrac{\textrm AB}{\textrm OA}$

Or, Tan 48.5° = $\dfrac{\textrm h}{\textrm x}$

Or, 1.13 = $\dfrac{\textrm 15}{\textrm x}$

∴ x = $\dfrac{\textrm 15}{\textrm 1.13}$

i.e x = 13.27 feet

So, The distance of base of wire to the base of tower = x = 13.27 ft

Hence, The distance of base of wire to the base of tower is 13.27 ft Answer

5 0

4 years ago