Answer:
0.00568
Explanation:
Recall that the fraction of radioactive material left after a time (t) is obtained from the formula;
N/No = (1/2)^t/t1/2
Where;
N= mass of radioactive material left after a time t
No= mass of radioactive material initially present
t= time taken for N mass of radioactive substance to remain = 60.0 days
t1/2= half-life of the radioactive substance= 8.04 days
Note that the required fraction is N/No, hence;
N/No= (1/2)^60.0/8.04
N/No= (1/2)^7.46
N/No = 0.00568
Answer: Sperm cell and Ovum
Explanation: Possibly
I think the answer would be protons
prometaphase ,metophase,and,more
