Answer & Step-by-step explanation:
The domain of a set of points refers to the input, also known as the x values. To find the domain, record all the x values given (x,y):
:Done
**The range is the output, aka the y values.
What is equation created from the sqrt(x+2)+2))^2
1 answer:
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Answer:
B) -2x+2y=-2
Step-by-step explanation:
we have
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (6,5)
see the attached figure
Remember that
If a equation is added to the system so that the solution does not change, then the solution of the system must be a solution of the equation added
<u><em>Verify each case</em></u>
The solution of the system is (6,5)
substitute the value of x and the value of y in each equation
case A) x-y=2
6-5=2
1=2 ----> is not true
therefore
This equation can't be added to the system
case B) -2x+2y=-2
-2(6)+2(5)=-2
-12+10=-2
-2=-2 ----> is true
therefore
This equation can be added to the system
case C) 3x+y=20
3(6)+5=20
18+5=20
23=20 ----> is not true
therefore
This equation can't be added to the system
case D) x+2y=18
5+2(6)=18
5+12=18
17=18 ----> is not true
therefore
This equation can't be added to the system
The measure of the ∠LQP is 120°
Step-by-step explanation:
The diagram of the question is as attached in the image.
LMNP is a square. We know that for a square all sides are equal and intersects at 90°
Hence, LM=MP=PN=LN
and ∠LMP= ∠MPN= ∠PNL= ∠NLM= 90°
Δ LMQ is an equilateral triangle
We know that for equilateral triangle all sides are equal and all angles are 60°
LM=LQ=QM=MP=PN=LN and
∠LQM= ∠QML= ∠MLQ= 60°
∠LQP= ∠LQM+ ∠MQP eq 1
In Δ MPQ
∠QPM=90° and ∠PMQ= 90°-60°=30°
Hence, ∠MQP= 180°-(90°+30°)=60°
Putting the value of ∠MQP and ∠LQM in equation 1
∠LQP= 60°+60°= 120°
Thus the measure of ∠LQP=120°
