Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.
<h3>What is the equation of a circle?</h3>
The equation of a circle of center
and radius r is given by:

In this problem, the circle is centered at the origin, hence
.
The circle contains the point (-13,0), hence the radius is found as follows:



Hence the equation is:

Then, we test if point (√5, 12) is on the circle:


25 + 144 = 169
Which is an identity, hence point (√5, 12) is on the circle.
More can be learned about the equation of a circle at brainly.com/question/24307696
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Lets find the area of the 2 rectangles on the left and right side.
8*7 (2) = 112 (Both rectangles in total)
Now lets find the rectangles on the front and back.
13*7 (2) = 182
Now, the top and bottom ones.
13*8 (2) = 208
Add them all together.
112+182+208 = 502
The surface area is 502.
Answer:
5x = 2x + 24 ( opposite angles are equal)
5x - 2x = 24
3x = 24
x = 24/3
x = 8
<h3>X = 8</h3>
5x = 5 × 8 = 40
2x + 24 = 2(8)+24 = 16 +24 = 40