Factor by grouping: 4. 3x² + 9x+4x+12
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We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:
For air-raid siren we have:
For jet engine noise we have:
To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
For air-raid siren we have:
For jet engine noise we have:
To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]