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3 years ago

How can revolting debt change from short term debt to long term debt

Mathematics

1 answer:

Juliette [100K]3 years ago

4 0

Answer:

what ,boy

Step-by-step exp lanation:

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WILL GIVE BRAINLIEST!!!!

boyakko [2]

Exponential functions are known to increase geometrically. An example of exponential function is p(x) = 500(1.02)^x

<h3>Exponential functions</h3>

Exponential functions are known to increase geometrically. The standard exponential function is given as:

y = ab^x

a is the base

x is the exponent

From the given options, the function written in this form is

p(x) = 500(1.02)^x. Hence an example of exponential function is

p(x) = 500(1.02)^x

Learn more on exponential function here: brainly.com/question/12940982

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2 years ago

The scale drawing shown above has a scale of 1inch:12feet. The redraw has a scale of 1inch:4feet. What will be the height of the

Tasya [4]

20% is the real answer yasss

3 0

3 years ago

Eric kept track of his days is a journal:

Leya [2.2K]

Answer:

Step-by-step explanation:

5 percent * 60 =

(5:100)* 60 =

(5* 60):100 =

300:100 = 3

7 0

2 years ago

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mafiozo [28]

Answer:

Side to side

I love all of hers

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3 years ago

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Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

Dividing by 0.5

A=152

7 0

3 years ago