<u><em>≡ We know that:</em></u>
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<u><em>≡ Solution:</em></u>
⇒![\sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%5D%7D%20)
⇒![\sqrt{[(3-(-4))^{2}+(-1-(-5))^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%283-%28-4%29%29%5E%7B2%7D%2B%28-1-%28-5%29%29%5E%7B2%7D%5D%7D%20)
⇒![\sqrt{[7^{2}+4^{2}]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B7%5E%7B2%7D%2B4%5E%7B2%7D%5D%7D%20)
⇒![\sqrt{[49+16]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B49%2B16%5D%7D%20)
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<u><em>≡ Solution:</em></u>
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Please help me if you help me the first one will get brainless
2 answers:
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Acc. to midpoint theorem,
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9
Answer:
Step-by-step explanation:
xy=-30
y=-30/x
x+y=-4
x-30/x=-4
x²-30=-4x
x²+4x-30=0