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2 years ago

15

Please help me if you help me the first one will get brainless

2 answers:

soldi70 [24.7K]2 years ago

7 0

Answer:

2/5

Step-by-step explanation:

The constant is 2/5 because it is not linked to a variable.

alexgriva [62]2 years ago

6 0

Answer:

2/5

Step-by-step explanation:

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.Jim opened an account with $400. The account pays three percent quarterly. How much is in the account at the end of two years?

podryga [215]

We may have this planned like this:
two years is 8 quarters
<span>Assuming simple interest, </span>
You will use the formula
<span>A = P(1+rt) </span>
<span>= 400(1+8*.03) </span>
<span>= 496
</span>I think this is the answer:) Hope it helps a lot

7 0

4 years ago

Find the difference using fraction bars or a paper and pencil. Write your answer in simplest form.

nasty-shy [4]

First, find the lowest common denominator. That is 12. You only have to change 3/4 into 12ths.

3/4 = 9/12

11/12 – 9/12 = 2/12 = 1/6

5 0

3 years ago

Read 2 more answers

Can someone help me with this maths equations please?

ale4655 [162]

Answer:

T=4B+10C

Step-by-step explanation:

for every bag there are 4 doughnuts

for every carton there are 10 doughnuts

4 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Simplify 10^–8. <br> 1/-100000000 <br> 1/100000000 <br> 1/-80 <br> 1/80

cluponka [151]

Answer:

C

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers