The 2-point form of the equation of a line can be written as ...
... y = (y2-y1)/(x2-x1)·(x -x1) +y1
For your points, this is ...
... y = (1-5)/(3-6)·(x -6) +5
... y = (4/3)(x -6) +5
It can also be written as
... y -5 = (4/3)(x -6)
Answer:
A exterior angle of a polygon is an angle outside the polygon formed by one of its sides and the extension of an adjacent side.
Line 1 and Line 4 are parallel lines
Solution:
General equation of a line:
y = mx + c
where m is the slope and c is the y-intercept of the line.
<u>To find the slope of each line:</u>
Line 1: 
Slope 
Line 2: 

Add 7 on both sides, we get

Slope 
Line 3: 
Slope 
Line 4: 
Subtract x from both sides, we get

Multiply by
on both sides, we get

Slope 
<em>Two lines are parallel, if their slopes are equal.</em>
From the above slopes,

Therefore Line 1 and Line 4 are parallel lines.
There are 6/10 left over. 6/10 reduces to 3/5.
A number can replaced with a variable like x
(X+3)4=16
4x+12=16
4x=4
X=1
(X/4)+3=24
X/4=21
X=84