So we know that
Year 1 = $55,000
Year 2 = 55000 + (55,000 x .04) = 55000 + 2200 = $57,200
Year 3 = 57200 + (57200 * .04) = 57200 + 2288 = $59,488
Year 4 = 59488 + (59488 * .04) = 59488 + 2379.52 = $61,867.52
Year 5 = 61867.52 + (61867.52 * .04) = 61867.52 + 2474.70 = $64,342.22
Year 6 = 64342.22 + (64342.22 * .04) = 64342.22 + 2573.69 = $66,915.91
Year 7 = 66915.91 + (66915.91 * .04) = 66915.91 + 2676.63 = $69,592.54
Year 8 = 69592.54 + (69592.54 * .04) = 69592.54 + 2783.70 = $72,376.24
Year 9 = 72376.24 + (72376.24 * .04) = 72376.24 + 2895.05 = $75,271.29
Year 10 = 75271.29 + (75271.29 * .04) = 75271.29 + 3010.85 = $78,282.14
So by the tenth year following graduation, the student would be making $78,282.14 a year. If you add up all of the values (Year 1 thru Year 10) you get a total income over ten years of $660,355.86
Answer:
B 36
Step-by-step explanation:
DC^2=6^2+8^2. AD=9cm DB=6cm
DC^2=36+64
DC^2=100
DC=√100
DC=10cm
AC^2=15^2+8^2
AC^2=225+64
AC^2=289
AC=√289
AC=17
P OF TRIANGLE ADC=10+9+17
=36cm
Hi there!
Since the denominators are the same in both fractions, this makes solving the problem super easy! All we need to do is to add the numbers across the fractions (numerator + numerator). We do not add the denominators together because they are the same.
WORK:
3/10 + 6/10 = 9/10
ANSWER:
Ross and Brady ate 9/10 of the pie together.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
The total is 300 cans. And 46percent of the total is 138. Therefore 138canned food was collected on Thursday.
