Question

Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded to the tenths?
Question 5 options:

20 cm


7.2 cm


4.5 c

Answer 1

Answer:

$4.5 cm=L2$

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

$H=\sqrt{L1^{2}+L2^{2} }$

Where:

$H=6 cm$

$L1=4 cm$

$L2=?$

We isolate our incognita an we get:

$\sqrt{H^{2}-L1^{2}} =L2$

We supplant with the given data:

$\sqrt{(6cm)^{2}-(4cm)^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{20cm^{2}} =L2$

$4.5 cm=L2$