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Ivahew [28]
2 years ago
15

Can somebody help me with this problem?

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
3 0
A=bh
A=53*47
A=<span>2491cm^2</span>
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3 years ago
the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence​
Crazy boy [7]

Answer:

The  sequence  is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms (S_{5}) = 250

or, \frac{n}{2} [{2a+(n-1)d}] = 250

or, \frac{5}{2} [2*10 + 4d]=250

or, \frac{5}{2} * 4[5+d]=250

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

8 0
3 years ago
Solve 2x+ 3=7<br> please ​
blondinia [14]

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Whenever moving a number to the other side you have to change the sign .

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3 years ago
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I hope this help you

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Find the inverse of the function.<br> y = 4x
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