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Maru [420]
3 years ago
6

What is the x and y intercept for this equation

Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0
What is the equation?
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And choose D is 38<br> Some help me
Dmitry_Shevchenko [17]

Answer:A

Step-by-step explanation:

it is equivalent to 180-128 because its the same as the angle under route 2

and above runway 2

4 0
3 years ago
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At a birthday party there were five more girls than boys. If the ratio of girls to boys was 4 to 3,
exis [7]

Let number if boys be x

  • No of girls=x+5

ATQ

\\ \sf\longmapsto \dfrac{x+5}{x}=\dfrac{4}{3}

\\ \sf\longmapsto 3(x+5)=4x

\\ \sf\longmapsto 3x+15=4x

\\ \sf\longmapsto 4x-3x=15

\\ \sf\longmapsto x=15

<h3>Number of girls</h3>

\\ \sf\longmapsto x+5=15+5=20

3 0
3 years ago
I NEED HELP FASTT!!! PLEASE
AysviL [449]

Answer:

5

Step-by-step explanation:

8x - 6 > 12 + 2x

Subtract 2x from each

8x -2x -6 > 12+2x-2x

6x -6 > 12

Add 6 to each side

6x -6+6 > 12+6

6x > 18

Divide by 6

6x/6 > 18/6

x > 3

The only value greater than 3 is 5

4 0
3 years ago
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A bookcase measures 13 feet wide and 24 feet tall wat wood the bookcases measurements be on the scale drawing using the scale 3c
antiseptic1488 [7]
Find out what 1 Foot per centimeter is (1.5 centimeters per foot)
Multiply 13 by 1.5 to find one side and 24 by 1.5 to find the other side
4 0
3 years ago
A track-and-field athlete releases a javelin. The height of the javelin as a function of time is shown on the graph below. Use t
Georgia [21]
Part 1:
 
 For this case we must see in the graph the axis of symmetry of the given parabola.
 We have then that the axis of symmetry is the vertical line t = 2.
 Answer:
 
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

 
Part 2:

 
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
 We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
 Then, we must observe the moment when it returns to be 20 feet above the ground.
 For this, observing the graph we see that:
 h (3) = 20 feet
 Therefore, a height of 20 feet is again reached in 3 seconds.
 Answer:
 
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
5 0
3 years ago
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