We are given

Since, we have to solve for F
so, we will isolate F on anyone side
step-1:
Multiply both sides by 60


step-2:
Divide both sides by 11


step-3:
Add both sides by 32


so, we get
................Answer
10 & 12
x = 1st consecutive even number
x + 2 = 2nd consecutive even number
x + x + 2 = 22
2x + 2 = 22
2x = 20
x = 10
x + 2 = 12
10 and 12 are the two consecutive even numbers
Consider the equation:

Subtracting '4' from both the sides of the equation, we get as


Squaring on both the sides of the equation, we get


Subtracting '2' from both the sides of the equation, we get

x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
Answer:
x= -10
Step-by-step explanation:
Brainliest please? :)