Question

In order for you to answer the question correctly, please use the following three images down below:

Answer 1

RS; RP; RQ; QP

Using RQ^2 = (RS)(RP) <--- That's the length of a secant and chord

to find RQ (You already know the length of RS and RP, because they are labelled, so the only other value that can be found is RQ)

QP (This is the only value that hasn't been found)

(14)(14+12) = RQ^2 -->

14(26) = RQ^2 -->

2sqrt(7*13) = RQ

QP = sqrt(26^2 - 364) = sqrt(676-364) = 2sqrt(78)

Answer 2

Answer:

RP; RS; RQ; Pythagorean theorem; PQ

Step-by-step explanation:

Using segments of secant and tangent theorem:

RQ² = RP × RS to find RQ

RQ² = 26×14

RQ = 2sqrt(91)

Then using pythagoras theorem, find PQ

PR² = PQ² + QR²

26² = PQ² + 364

PQ² = 312

PQ = 2sqrt(78)