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Dafna1 [17]
3 years ago
5

Esmerelda is five times as old as Ruth. Four years ago, the sum of their ages was 22 years. How old is each now?

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0

Answer:

Ruth is  x+4=7/3+4,   esmerelda  is  5x+4=35/3+4

Step-by-step explanation:

if Ruth is x, esmerelda is 5x,

four years ago,

Ruth is x+4,  esmerelda is 5x+4,  depend on the sum, we get:

x+4+5x+4=22, x=7/3

so:

Ruth is  x+4=7/3+4,   esmerelda  is  5x+4=35/3+4

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Please help me I do not understand this!​
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How can we use ratios and proportional relationships to help us in our daily lives?
ehidna [41]

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In cooking (recipes).

Step-by-step explanation:

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6 0
3 years ago
If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi
Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = \mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2} --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval  

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16

34 \times 1+\frac{1}{2} \times a \times 1^{2}=18

34+\frac{a}{2}=18

\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0
3 years ago
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