Question

To rent a certain meeting room, a college charges a reservation fee of $19 and an additional fee of $6 per hour. The chemistry club wants to spend less than $91 on renting a room. What are the possible numbers of hours the chemistry club could rent the meeting room? Use t for the number of hours. Write your answer as an inequality solved for t,

Answer 1

T= # of rental hours


Multiply number of hours rented by the cost per hour, add that total to the reservation fee. The total needs to be less than $91.


Reservation + ($ per hr * # hrs) < $91

$19 + $6t < $91
subtract 19 from both sides

6t < 72
divide both sides by 6

t < 12


ANSWER: To spend less than $91, they need to rent the room less than 12 hours.

Hope this helps! :)