Answer:

Step-by-step explanation:
To solve this problem we need to be familiar with the formula for the surface area of a cone:

We are given the length of a side and the diameter, to calculate the radius divide the diameter in half:

To calculate the height of the cone, we must use the Pythagorean Theorem:

We can treat the side length as the hypotenuse
, the radius as the base
, and solve for height
. Set the expression up like this:

Now we can plug into our original formula:

68+32=100 he used a $100 bill
Answer:
Step-by-step explanation:
( 2 , 26 )
( 0 , 4 )
m = (26 - 4 ) / ( 2 - 0 ) = 11
Cost of each game is $11
Answer:
For the first picture: the answers A
For the second picture: it is also A
Step-by-step explanation:
I put each fraction into desmos for the second picture and the one that matched the image was A.
For the first image i picked A because 10 is a constant without a variable and is not a coefficient.
(3,2). 3^2 + 2^2 = 13 2(3)-2= 4 Works for both, hence this is the intersecting point of the two lines.