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4 & 7/8 divided by 1 & 1/6

belka [17]

Answer:

$4 \frac{5}{28}$

Step-by-step explanation:

$4 \frac{7}{8} \div 1 \frac{1}{6}$

Convert the mixed numbers above to improper fractions

$= \frac{39}{8} \div \frac{7}{6}$

Rule of basic operation states that when dividing fractions, the division sign changes to multiplication sign thus turn the right hand side of the fraction inversely such that 7/6 becomes 6/7.

$= \frac{39}{8} \times \frac{6}{7}$

$= \frac{39 \times 6}{8 \times 7}$

$= \frac{234}{56}$

Converting the answer above to mixed number result to:

$= 4 \frac{5}{28}$

4 0

3 years ago

The measure of one of the acute angles in a right triangle is (2y) what is the other acute angle

skelet666 [1.2K]

The measure of the other acute angle in the right triangle is 90 - 2y

<h3>How to determine the other acute angle?</h3>

The given parameters in the question are:

Shape = right triangle

Acute angle = 2y

The measures of acute angles in a right triangle add up to 90

This can be represented mathematically as

Acute angle + Other angle = 90

Substitute the known values in the above equation, so, we have the following representation

2y + Other angle = 90

This gives

Other angle = 90 - 2y

Hence, the other angle is 90 - 2y

Read more about acute angles at

brainly.com/question/16449433

#SPJ1

7 0

1 year ago

1. What is the solution of the system?

andreyandreev [35.5K]

Answer:

The given system of equations has solutions below:

1) The solution is (2,3)

2) The solution is ( $\frac{-8}{7}, \frac{5}{7}$ )

3) The solution is infinitely many solutions

4) No solution

Step-by-step explanation:

Given system of equation are

$-x+2y=4\hfill (1)$

$-4x+y=-5\hfill (2)$

To solve equation by using elimination method

Multiply eqn (2) into 2

$-8x+2y=-10\hfill (3)$

Now subtracting (1) and (3)

$-x+2y=4$

$-8x+2y=-10$

_________________

7x=14

x= $\frac{14}{7}$

$x=2$

Substitute x=2 in equation (1)

-2+2y=4

2y=4+2

$y=\frac{6}{2}$

y=3

Therefore the solution is (2,3)

2) Given equation is

$-2x+y=3\hfill (1)$

4y-4=x

Rewritting as below

$x-4y=-4\hfill (2)$

To solve equation by using elimination method

multiply (2) into 2

$2x-8y=-8\hfill (3)$

Adding (1) and (3)

-2x+y=3

2x-8y=-8

________

-7y=-5

$y=\frac{5}{7}$

substitute $y=\frac{5}{7}$ in (1)

$-2x+\frac{5}{7}=3$

$-2x=3-\frac{5}{7}$

$-2x=\frac{21-5}{7}$

$x=-\frac{8}{7}$

Therefore the solution is ( $\frac{-8}{7},\frac{5}{7}$ )

3) Given equation is $6x+2y=10\hfill (1)$

$3x+y=5\hfill (2)$

equation (1) can be written as

2(3x+y)=10

$3x+y=\frac{10}{2}$

3x+y=5

Therefore equations (1) and (2) are same therefore it has infinitely many solutions

4) Given equation is $-x-2y=14\hfill (1)$

$-2x-4y=12\hfill (2)$

multiply equation (1) into 2

$-2x-4y=28\hfill (3)$

To solve equation by using elimination method

subtracting (2) and (3)

-2x-4y=28

-2x-4y=12

_______

$28\neq -12$

therefore it has no solution

4 0

2 years ago

What is the image of (-7,-8) after a dilation by a scale factor of 4 centered at the origin

padilas [110]

Have you ever heard the tragedy of darth plagues the wise

5 0

2 years ago

Any help? I'm struggling.

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

a=-7

r=21/-7=-3

$a_{15}=a r^{n-1}=-7(-3)^{15-1}=-7(-3)^{14}=-33480783$

4 0

2 years ago

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