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3 years ago

How can you use equivalent fractions to know that 43/200 is between 1/5 and 1/4

Mathematics

1 answer:

Vikki [24]3 years ago

7 0

Multiply 1/5 and 1/4 so that everything has a common denominator of 200.

1/5*40/40 = 40/200
1/4*50/50 = 50/200

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It takes 8,000 pounds of sand to make a beach volleyball court. If the organizers of a tournament purchase 24,000 pounds of sand

Alja [10]

Answer:

3 courts

Step-by-step explanation:

8,000 = 1 court

24,000 = x courts

8,000 x ? = 24,000

8,000 x <u>3</u> = 24,000

1 x 3 = 3 courts

6 0

3 years ago

When working with positive and negative numbers, the further left you move on the number line, the________the numbers are and th

USPshnik [31]

The further left a number is the less it is
The further right a number is the greater it is

8 0

3 years ago

What is the distance between the two points? (-18, -6) & (-18,-1)

Hitman42 [59]

Answer:

Step-by-step explanation:

D² = ( x2 - x1 )² + ( y2 - y1 )²

= [ (-18) - (-18) ]² + [ (-1) - (-6) ]²

= ( -1 + 6 )²

D² = ( 5 )²

hence, D = 5

5 0

3 years ago

Read 2 more answers

Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500

Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 500, \pi = \frac{421}{500} = 0.842$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874$

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0

3 years ago

I don't know how to do this problem.....please help

Lemur [1.5K]

I hope this helps you

5 0

3 years ago