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amid [387]
3 years ago
13

Why do people always use drugs

Biology
1 answer:
ipn [44]3 years ago
4 0

Answer:

I have been around it my whole life people just get addicted. Its like this game that you realy love so you play it over and over again.

Explanation:

You might be interested in
Where should the label for the dependent variable be written for this scatter plot?
Nezavi [6.7K]

Answer:

B. Position B

Explanation:

The values for dependent variable are plotted on the y-axis (vertical) on a scatter plot. Therefore, the label for the dependent variable would be written along the vertical axis for the scatter plot, at position B.

The label for independent variable would be written along the horizontal axis for the scatter plot, at position C.

The answer is "B. Position B"

4 0
3 years ago
Select ALL the correct answers.
tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}

10th\ run = 9

So:

B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

Required

Select all true statements

(a) & (d) Median Comparisons

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}                         B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

n = 9                                                         n = 10

Arrange the data:

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

                               Median = \frac{n + 1}{2}th

Median = \frac{9 + 1}{2}th                            Median = \frac{10 + 1}{2}th

Median = \frac{10}{2}th                              Median = \frac{11}{2}th

Median = 5th                                 Median = 5.5}th --- average of 5th and 6th

Median = 2                                    Median = \frac{2+2}{2} = 2

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

n = 9                                                         n = 10

First, calculate the lower quartile (Q1)

Q_1 = \frac{n + 1}{4}th[Odd n]             Q_1 = \frac{n}{4}th [Even n]

Q_1 = \frac{9 + 1}{4}th                            Q_1 = \frac{10}{4}th

Q_1 = \frac{10}{4}th                              Q_1 = 2.5

Q_1 = 2.5th                              

This means that:

Q_1 = 2nd + 0.5(3rd - 2nd)              Q_1 = 2nd + 0.5(3rd - 2nd)

Q_1 = 1 + 0.5(1- 1)                   Q_1 = 1+ 0.5(1 - 1)                      

Q_1 = 1                                       Q_1 = 1

Next, calculate the upper quartile (Q3)

Q_3 = \frac{3}{4}(n + 1)th [Odd n]             Q_3 = \frac{3}{4}(n)th [Even n]

Q_3 = \frac{3}{4}(9 + 1)th                            Q_3 = \frac{30}{4}th

Q_3 = \frac{30}{4}th                                     Q_3 = 7.5th  

Q_3 = 7.5th                                    

This means that:

Q_3 = 7th + 0.5(8th- 7th)           Q_3 = 7th + 0.5(8th- 7th)

Q_3 = 2 + 0.5(3- 2)                       Q_3 = 2+ 0.5(4 - 2)                      

Q_3 = 2.5                                       Q_3 = 3

The interquartile range is  IQR = Q_3 - Q_1

So, we have:

IQR = 2.5 - 1                  IQR = 3 - 1

IQR = 1.5                       IQR  =2

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0
3 years ago
When is selective breeding okay and when is it not? Provide evidence.
jonny [76]

Answer:

Farmers have been using selective breeding for improving their crop qualities and producing animals with better characteristics.

improved so that mankind can benefit from it.

Selective breeding is not okay on a bigger level where it might eradicate the natural varieties of plants and animals completely.  When done on a larger level, the wild-type traits of plants and animals will change and be removed completely. This will lead to lesser genetic diversity.

5 0
4 years ago
A scientist discovers at the end of an experiment that his hypothesis was
sergejj [24]

Answer:

C. Yes, the results of his experiment were probably inaccurate the

first time.

7 0
2 years ago
Two yeast cells were placed into a special container to which food was continually added, to keep it at a constant concentration
Andrews [41]

Answer:

Answer to Two yeast cells were placed into a special container to which food was continually ... All Other Factors Were Set For Optimal Yeast Growth (for Example, ... The Population Was Sampled Every Hour For 21 Hours And The Results Of The ... to which food was continually added, to keep it at a constant concentration.

Explanation:

Answer to Two yeast cells were placed into a special container to which food was continually ... All Other Factors Were Set For Optimal Yeast Growth (for Example, ... The Population Was Sampled Every Hour For 21 Hours And The Results Of The ... to which food was continually added, to keep it at a constant concentration.

4 0
3 years ago
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