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VARVARA [1.3K]
3 years ago
11

Mariah purchased a car for $8,599. If the rate of depreciation is 2.5%, what will the value of the car be after 4 years? Round y

our answer to the nearest hundredth.
Mathematics
1 answer:
Firdavs [7]3 years ago
3 0

Answer:

\$7,770.81  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$8,599\\r=2.5\%=0.025\\x=4\ years

substitute

V=\$8,599(1-0.025)^{4}=\$7,770.81  

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Cos A = adj/hyp =  3/5

Tan A = opp/adj =  4/3

Cos 27 = 0.8910065...  --> 0.89

You can just plug that into your graphing calculator, just make sure the degree mode is on.

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3 years ago
You are selling t-shirt for $15 each as a fundraiser. You sold 17 less today then you did yesterday. Altogether you have raised
jeyben [28]

Answer: 28

Step-by-step explanation:?

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3 years ago
A shipping company charges a $6 flat fee for a package, plus a fee based on the weight of the package. The company charges $1.25
Musya8 [376]

Answer: 11.2 pounds is the max weight of the package he can have.

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3 years ago
(X to the fourth power) squared equals
Viktor [21]

Answer:

(x^4)^2=x^8

Step-by-step explanation:

Because of the power of a power property, which states that (x^n)^m=x^{n\times{m}}, where m and n are real numbers, the expression you mentioned can be simplified by applying this property like this: (x^4)^2=x^{4\times2}=x^8

4 0
3 years ago
Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
4 years ago
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