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Tanzania [10]
2 years ago
6

A man has 33 coins in his pocket, all of which are dimes and quarters. If the total value of his change

Mathematics
1 answer:
kupik [55]2 years ago
3 0

Answer:

Number of dimes = 16

Number of quarters = 17

====================================================

Work Shown:

d = number of dimes

q = number of quarters

d+q = 33 coins total, this solves to d = 33-q

10d = value of all the dimes in cents

25q = value of all the quarters in cents

10d+25q = 585 cents total

--------------

Plug in d = 33-q and solve for q

10d+25q = 585

10(33-q) + 25q = 585

330-10q+25q = 585

15q+330 = 585

15q = 585-330

15q = 255

q = 255/15

q = 17

The man has 17 quarters

d = 33-q = 33-17 = 16

He also has 16 dimes.

--------------

Check:

16 dimes + 17 quarters = 33 coins total

16 dimes = 16*10 = 160 cents

17 quarters = 17*25 = 425 cents

160 cents + 425 cents = 585 cents

The answer is confirmed.

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A family wants to build a rectangular garden on one side of a barn. If 600 feet of fencing is available to use, then what is the
vovangra [49]

Answer: (A) A=300l-l^{2}

               (B) Length varies between 1 and 150

               (C) Largest area is 22500ft²

Step-by-step explanation: Suppose length is l and width is w.

The rectangular garden has perimeter of 600ft, which is mathematically represented as

2l+2w=600

Area of a rectangle is calculated as

A=lw

Now, we have a system of equations:

2l+2w=600

A=lw

Isolate w, so we have l:

2w=600-2l

w = 300 - l

Substitute in the area equation:

A = l(300 - l)

A = 300l - l²

(A) <u>Function of area in terms of length is given by </u><u>A = 300l - l²</u>

(B) The practical domain for this function is values between 1 and 150.

(C) For the largest area, we need to determine the largest garden possible. For that, we take first derivative of the function:

A' = 300 - 2l

Find the values of l when A'=0:

300 - 2l = 0

2l = 300

l = 150

Replace l in the equation:

w = 300 - 150

w = 150

Now, calculate the largest area:

A = 150*150

A = 22500

<u>The largest area the fence can enclose is </u><u>22500ft².</u>

4 0
2 years ago
Can someone please help me and explain?
Aleks [24]
Have a nice day hope this helps

7 0
3 years ago
Aubrey ran 13 1/6 miles and walked 9 5/6 miles. How much farther did Aubrey run than walk?
leonid [27]

Answer:

Aubrey ran 3 1/3 miles further than what she walked.

Step-by-step explanation:

This would be your basic subtraction problem. So, 13 1/6 - 9 5/6.

Since you can't subtract 5/6 from 1/6, let's borrow from 13. Now, instead of 13, it would be 12. Adding the whole (1) or 6/6 to the 1/6, you'll get 7/6. Now you can subtract. 7/6 - 5/6 = 2/6. Moving on, 12 - 9 = 3.

Therefore, your answer is 3 2/6. In simplified terms, it would be 3 1/3.

3 0
2 years ago
Never mind. I meant these problems. Please find the mean, median, and mode.
Sergio [31]
Median mean to find the center of the data
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