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2 years ago

A man has 33 coins in his pocket, all of which are dimes and quarters. If the total value of his change

Mathematics

1 answer:

kupik [55]2 years ago

3 0

Answer:

Number of dimes = 16

Number of quarters = 17

====================================================

Work Shown:

d = number of dimes

q = number of quarters

d+q = 33 coins total, this solves to d = 33-q

10d = value of all the dimes in cents

25q = value of all the quarters in cents

10d+25q = 585 cents total

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Plug in d = 33-q and solve for q

10d+25q = 585

10(33-q) + 25q = 585

330-10q+25q = 585

15q+330 = 585

15q = 585-330

15q = 255

q = 255/15

q = 17

The man has 17 quarters

d = 33-q = 33-17 = 16

He also has 16 dimes.

--------------

Check:

16 dimes + 17 quarters = 33 coins total

16 dimes = 16*10 = 160 cents

17 quarters = 17*25 = 425 cents

160 cents + 425 cents = 585 cents

The answer is confirmed.

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