Answer:
1) x - 4 is greater than or equal to 18
x is greater than or equal to 22
2) 12 + x is less then or equal to 17
x is less the or equal to 5
3) 23 is less than x + 16
7 is less than x
4) -6 + x is greater than or equal to -7
x is greater than or equal to -1
Answer:
The price of the admission is 15.
Step-by-step explanation:
From the information given, you can write the following equations:
a+3e=45 (1)
a+5e=65 (2), where:
a is the admission cost
e is the exhibition cost
First, you can solve for a in (1):
a=45-3e (3)
Second, you can replace (3) in (2):
45-3e+5e=65
45+2e=65
2e=65-45
2e=20
e=20/2
e=10
Finally, you can replace the value of e in (3):
a=45-3e
a=45-3(10)
a=45-30
a=15
According to this, the price of the admission is 15.
Answer:
A(x) = 4x^2 + 330x + 4356
Step-by-step explanation:
width of park: x
length of park: 4x
width + path width = x + 66
length + path width = 4x + 66
area = (x + 66)(4x + 66)
area = 4x^2 + 66x + 264x + 4356
area = 4x^2 + 330x + 4356
A(x) = 4x^2 + 330x + 4356
I must assume that you meant the following:
10(Q-3R)
P = ----------------
R
Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.
Rearranging these terms so that powers of R are in descending order:
30R^2 - 10RQ + PR = 0
Factoring out R, we get
R(30R - 10Q + P) = 0. This has two solutions:
R = 0, and 10Q - P
30R = 10Q - P, so that R = --------------
30