A population of naked mole rats begins with 250 individuals in 2015. The population has a carrying capacity of 1,500 individuals
. If the population has an intrinsic rate of increase equal to 0.8, how large is the population in 2016?
please show me step by step, thank you!
1 answer:
dN/dT = rK (K-N)/K
Here, K is carrying capacity
N = Population size
r = Intrinsic rate
dN/dT = 0.8*250 (1500-250)/1500
dN/dT = 166.66 that is equivalent to 167 animal in a year
Thus, in 2015, there would be 250 individuals and in 2016, there would be 260+167 = 417 animals.
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