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denpristay [2]
3 years ago
9

Big will's ice cream cone contains 16 grams of saturated fat. This is 80% of his total daily allowance. What big will's total da

ily allowance of saturated fat in grams?
Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

20 grams

Step-by-step explanation:

Let x be the total allowance of fat

16 grams is 80% of his total allowance

x * 80% = 16

Change percent to a decimal

x *.8 = 16

Divide each side by .9

.8x/.8 = 16/.8

x = 20

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Sladkaya [172]

Answer:

14+21

Step-by-step explanation:

because, 14+21 =35

21 is 7 more bigger than 14

5 0
2 years ago
Without subtracting 8.5 - 4.64, determine what digit will be in the hundredths place. Explain
murzikaleks [220]
8.5 is the same as 8.50, right? So just take the digit in the hundredth place of both decimals and subtract. You'd be doing 0-4 so you can go ahead and borrow a number to make 10-4, which equals 6. So without subtracting 8.5 and 4.64, you can determine that 6 will be in the hundredth place. Hope this helps!
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3 years ago
How to solve 37=-3+5(x+6)
zavuch27 [327]
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37= -3+5x+30 (subtract 30 on both sides)

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7 0
3 years ago
Use the equation v = StartFraction 10 Over p EndFraction to determine the pressure when the volume is 10 liters. A. 10 c. 100 b.
Galina-37 [17]

The value of the pressure is 1 when the value of volume is 10 liters, the correct option is D.

<h3>What is the pressure?</h3>

Pressure is defined as the physical force exerted on an object.

The force applied is perpendicular to the surface of objects per unit area.

Given

The equation is

\rm V=\dfrac{10}{p}

Where the v is the volume and p is the pressure.

The value of p when the value of volume v is 10 liters is;

\rm V=\dfrac{10}{p}\\\\\rm 10=\dfrac{10}{p}\\\\P = \dfrac{10}{10}\\\\P=1

Hence, the value of the pressure is 1.

To know more abour pressure click the link given below.

brainly.com/question/17799294

6 0
2 years ago
Log(1+y) - log(1-y) = log x in 2 decimal places, express y in terms of x
GaryK [48]

Answer: y = \frac{x-1}{x+1}

Step-by-step explanation:

log(1+y) - log(1-y) = log x \\log\frac{1+y}{1-y} =log x\\x = \frac{1+y}{1-y}\\x(1-y)=1+y\\x-xy=1+y\\x-1 = xy+y\\y(x+1)=x-1\\y=\frac{x-1}{x+1}

6 0
3 years ago
Read 2 more answers
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