The maximum value of the objective function is 31.787
<h3>How to maximize the function?</h3>
The given parameters are:
Objective function:
Max P = 4x + 5y + 21
Subject to:
y- x < 1
21x + 7y < 25
x>-2, y>-4
Rewrite the inequalities as equation
y - x = 1
21x + 7y = 25
Add x to both sides in y - x = 1
y = x + 1
Substitute y = x + 1 in 21x + 7y = 25
21x + 7x + 7 = 25
Evaluate the like terms
28x = 18
Divide both sides by 28
x = 0.643
Substitute x = 0.643 in y = x + 1
y = 0.643 + 1
y = 1.643
So, we have:
Max P = 4x + 5y + 21
This gives
P = 4 * 0.643 + 5* 1.643 + 21
Evaluate
P = 31.787
Hence, the maximum value of the objective function is 31.787
Read more about maximum functions at:
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Can you take a more clear photo ?
Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have
. Simplifying a bit gives us
and
. Raising that number inside the parenthesis to the 15th power gives us
. Multiplying to finish means that A(t) = $317.22
If the equation is 3+x=10, x is equal to 7
