You have a 1/2 (or 50 percent) chance of picking a cheese sandwich at random out of your total of 8 sandwiches, 4 out of which are cheese. Simplifying the fraction, you'd get 1/2 probability. Hope this helps!
Consider, pls, this explanation + solution:
according to the given equation the centre of this circle is in the poit (6;7) and its radius =4 units.
Using this data, it is possible to define right choice: D.
answer: graph D.
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
Answer:
100000 ways
Step-by-step explanation:
Given that there are 10 distinct integers.
5 numbers are drawn with replacement
Prob that each number is drawn will have 10 choices
So each of 5 number can be selected in 10 ways
No of ways to select 5 numbers with replacement
= 10^5
=100000 ways
