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grandymaker [24]
3 years ago
15

U scared fromlizard or cockroache?​

Mathematics
2 answers:
dangina [55]3 years ago
3 0

Hello There!

<u>ANSWER:</u>

<u />

Cockroache.

Because, it just looks scary, and they skin colors just give me poop vibes.

:)

AnimeVines

fomenos3 years ago
3 0

Answer:

<h2>cockroach </h2>

Step-by-step explanation:

  • bcos the insect it's looked like weird
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(x-1/x ²-4) + (1/x-2)
kodGreya [7K]

Answer:

  (2x+1)/(x^2 -4)

Step-by-step explanation:

When you add fractions (or rational expressions) you need to express each of them over a common denominator, so you can add the numerators. (Parentheses or other grouping symbols are required.)

  \dfrac{x-1}{x^2-4}+\dfrac{1}{x-2}=\dfrac{x-1}{(x-2)(x+2)}+\dfrac{(1)(x+2)}{(x-2)(x+2)} \qquad\text{now we have a common denominator}\\\\=\dfrac{(x-1)+(x+2)}{(x-2)(x+2)}=\dfrac{2x+1}{(x-2)(x+2)}=\dfrac{2x+1}{x^2-4}

You factor the denominator on the left so you can see what factors are missing from the denominator on the right.

__

<em>Numerical example</em>

Suppose you want to add the fractions 4/15 and 3/5. You would factor the denominator 15 into 3·5, so you can see that the fraction 3/5 needs to be multiplied by (3/3) in order to give it a denominator of 15. Once the two fractions have a common denominator, you can add their numerators.

  4/15 + 3/5 = 4/15 + (3/5)(3/3)

  = 4/15 + 9/15

  = (4+9)/15 = 13/15

_____

<em>Comment on grouping symbols</em>

When a rational expression is typeset, the division bar of the fraction identifies the numerator and the denominator:

  \dfrac{x-1}{x^2-4}

When you write it in plain text as ...

  x - 1/x^2 -4

this becomes a 3-term expression:

  (x) -(1/x^2) -(4)

which is very different from what you may intend. In order to match the original typeset expression, parentheses must be added to show the group in the numerator and the group in the denominator:

  (x -1)/(x^2 -4)

The same holds for exponents. The superscript position in a typeset expression tells you what the exponent is. When you write the same thing in plain text, parentheses are needed to show the exponent group.

  3^{x-1} = 3^(x -1) ≠ 3^x -1

7 0
4 years ago
Ramal filled 3 pages in a stamp album this is one sixth of the pages in the album how many pages are there in ramals stamp album
Akimi4 [234]
There are 18 pages in Ramal's stamp album
To get this, use the equation : 1/6p = 3
P represents pages, so 6 * 3 is 18 pages.
4 0
3 years ago
Read 2 more answers
Please help me guys idk what it is
goldfiish [28.3K]

Answer: the answer would be one because they are both the same length and there is an acute angle

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help.........
posledela

Step-by-step explanation:

A e f=180-100

=80

Efd= 360-80-100-40-35

=105

4 0
3 years ago
The quality-assurance program for a certain adhesive formulation process involves measuring how well the adhesive sticks a piece
Svetach [21]

Answer:

A) P ( X ≤ 160 ) = 0

B) Unusually small

C) process was no longer functioning correctly

D) P ( X ≥ 203 ) = 0.3821

E) Not unusually large

F) No-Evidence

G) P ( X ≤ 195 ) = 0.3085

H) Not unusually small

I) No evidence

Step-by-step explanation:

Given:-

- The random variable (X) denotes the adhesive strength is normally distributed with mean u = 200 N and standard deviation s.d = 10 N.

                            X ~ N ( 200 , 10^2 )

Solution:-

A) Find P(X ≤ 160), under the assumption that the process is functioning correctly.

- Determine the Z-score value:

                      Z-score = ( X - u ) / s.d

                                    = ( 160 - 200 ) / 10

                                    = -4

- Use the standardized z-table to determine the probability:

                      P ( X ≤ 160 ) = P ( Z ≤ -4 )

                                           = 0

- Assuming the process is functioning properly then the adhesive strength of X = 160 N would be considered unusually small since the probability of occurrence is approximately 0.

- If we were to observe an adhesive strength process that gives us the value of 160 N can imply that the process is not functioning properly as its outside the 3 standard deviations from the mean value. ( Conclusive Evidence )

D) Find P(X ≥ 203), under the assumption that the process is functioning correctly.

- Determine the Z-score value:

                      Z-score = ( X - u ) / s.d

                                    = ( 203 - 200 ) / 10

                                    = 0.3

- Use the standardized z-table to determine the probability:

                      P ( X ≥ 203 ) = P ( Z ≥ 0.3 )

                                           = 0.3821

- Assuming the process is functioning properly then the adhesive strength of X = 203 N would be not be considered unusually small since the probability of occurrence is in the heart of the bell curve.

- If we were to observe an adhesive strength process that gives us the value of 203 N can imply that the process is functioning properly as its within 1 standard deviation from the mean value. ( No evidence )

G) Find P(X ≤ 195), under the assumption that the process is functioning correctly.

- Determine the Z-score value:

                      Z-score = ( X - u ) / s.d

                                    = ( 195 - 200 ) / 10

                                    = -0.5

- Use the standardized z-table to determine the probability:

                      P ( X ≤ 195 ) = P ( Z ≤ -0.5 )

                                           = 0.3085

- Assuming the process is functioning properly then the adhesive strength of X = 195 N would be not be considered unusually small since the probability of occurrence is in the heart of the bell curve.

- If we were to observe an adhesive strength process that gives us the value of 195 N can imply that the process is functioning properly as its within 1 standard deviation from the mean value. ( No evidence )

5 0
3 years ago
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