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sladkih [1.3K]
3 years ago
11

How do you unFOIL a trionomial

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0
You factor it. You can use the quadratic formula, completing the square, graphing, and the MATER P method
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If f, g, h
ale4655 [162]

Answer:

F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(3) = 3(3)^2 + 1 = 27 + 1 = 28

G(4) = 2(4) - 3 = 8 - 3 = 5

2H(5) = 2(5) = 10

F(3) + G(4) - 2H(5) = 28 + 5 - 10

F(3) + G(4) - 2H(5) = 23

Step-by-step explanation:

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6 0
3 years ago
Simplify 3 square root of 512
Karolina [17]

Answer:

8

Step-by-step explanation:

not sure if this is what ur looking for sorry

7 0
2 years ago
Read 2 more answers
Solve<br>4(2x - 3) = 6x + 2​
vaieri [72.5K]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

4(2x - 3) = 6x + 2

Expand it:

8x - 12 = 6x + 2

+ 12 to both sides

8x = 6x + 14

- 6x from both sides

2x = 14

Divide both sides by  2:

x = 7

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4 0
3 years ago
Find the difference.<br> (−2g+7)−(g+11) =
Dmitry_Shevchenko [17]

Answer:

-3g-4

Step-by-step explanation:

(-2g+7)-(g+11)= -2g+7-g-11= -3g-4

7 0
2 years ago
Read 2 more answers
This is Algebra btw.
Brums [2.3K]
<h2>Step-by-step explanation:</h2>

Given equations;

y₁ = 3x - 8               -------------------(i)

y₂ = 0.5x + 7          --------------------(ii)

To fill the table, substitute the values of x into equations (i) and (ii)

=> At x = 0

y₁ = 3(0) - 8 = -8

y₂ = 0.5(0) + 7 = 7

=> At x = 1

y₁ = 3(1) - 8 = -5

y₂ = 0.5(1) + 7 = 7.5

=> At x = 2

y₁ = 3(2) - 8 = -2

y₂ = 0.5(2) + 7 = 8

=> At x = 3

y₁ = 3(3) - 8 = 1

y₂ = 0.5(3) + 7 = 8.5

=> At x = 4

y₁ = 3(4) - 8 = 4

y₂ = 0.5(4) + 7 = 9

=> At x = 5

y₁ = 3(5) - 8 = 7

y₂ = 0.5(5) + 7 = 9.5

=> At x = 6

y₁ = 3(6) - 8 = 10

y₂ = 0.5(6) + 7 = 10

=> At x = 7

y₁ = 3(7) - 8 = 13

y₂ = 0.5(7) + 7 = 10.5

=> At x = 8

y₁ = 3(8) - 8 = 16

y₂ = 0.5(8) + 7 = 11

=> At x = 9

y₁ = 3(9) - 8 = 19

y₂ = 0.5(9) + 7 = 11.5

=> At x = 10

y₁ = 3(10) - 8 = 22

y₂ = 0.5(10) + 7 = 12

The complete table is attached to this response.

(ii) To find the solution of the system of equations using the table, we find the value of x for which y₁ and y₂ are the same.

As shown in the table, that value of <em>x = 6</em>. At this value of x, the values of y₁ and y₂ are both 10.

5 0
3 years ago
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