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dangina [55]
3 years ago
14

Write the equations after translating the graph of y = | 1/2x−2|+3, one unit to the right

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

we are given

y=|2x|-1

we are given to translate this equation

Whenever we translate any function to right side by 'c' units

we can replace x as x-c

Here , we have to translate one unit right

so, we can replace x as x-1

and we get

y=| 2( x-1 ) | 1

Hope this helps <3

AveGali [126]3 years ago
6 0

y=|\dfrac{1}{2}x-2|+3

Since we are translating this graph one unit to the right, replace x with (x-1)

Note: If you are translating a graph to the left by k units, replace x with (x+k), and if by the right, replace x with (x-k)

y=|\dfrac{1}{2}(x-1)-2|+3

After simplifying, we now have the following equation:

=|\dfrac{1}{2}x-\dfrac{5}{2}|+3

This is the new equation. Let me know if you need any clarifications, thanks!

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The reason why is because the sum of two sides is always larger than the value of the third side.

I hope that this helps.

7 0
3 years ago
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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

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3 years ago
In general, the median of a data set is less resistant to outliers than the mean. A. True B. False
Leto [7]
A. true, the median of a data set is less resistant to outliers than the mean
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Select the decimal that is equivalent to 1/8
iogann1982 [59]
The answer is 0.125....................................
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Jonathan’s class has 30 boys. Of the students in his class, 60% are girls. How many girls are in Jonathan’s class?
raketka [301]

Answer:

45 girls

Step-by-step explanation:

  • Remark
  • There are only 2 choices for gender. So if the class is 60% girls, the there must be 100 - 60 = 40% for the boys.
  • But we are told that the boys are 30 in number.
  • Let x = the total number of students.

Solution

  • 40/100 * x = 30              Change the % to a decimal
  • 0.4 x = 30                       Divide both sides by 0.4
  • 0.4 x / 0.4 = 30 / 0.4      Do the division
  • x = 30/0.4
  • x = 75 students in total

Formula

Total of Boys and Girls = Number of boys + number of girls.

Givens

  • Total = 75
  • Number of boys = 30

Solution II

  • 75 = x + 30                 Subtract 30 from each side
  • 75 - 30 = x +30 - 30
  • 45 = x
  • There are 45 girls in the class.
5 0
4 years ago
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