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dangina [55]
3 years ago
14

Write the equations after translating the graph of y = | 1/2x−2|+3, one unit to the right

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

we are given

y=|2x|-1

we are given to translate this equation

Whenever we translate any function to right side by 'c' units

we can replace x as x-c

Here , we have to translate one unit right

so, we can replace x as x-1

and we get

y=| 2( x-1 ) | 1

Hope this helps <3

AveGali [126]3 years ago
6 0

y=|\dfrac{1}{2}x-2|+3

Since we are translating this graph one unit to the right, replace x with (x-1)

Note: If you are translating a graph to the left by k units, replace x with (x+k), and if by the right, replace x with (x-k)

y=|\dfrac{1}{2}(x-1)-2|+3

After simplifying, we now have the following equation:

=|\dfrac{1}{2}x-\dfrac{5}{2}|+3

This is the new equation. Let me know if you need any clarifications, thanks!

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___a value used to represent a true measurement that is not exact when an exact answer is not possible
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An estimate

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Fifty balls are numbered 1 to 50 and a red dot is painted on those balls that are a multiple of 6. The balls are mixed into a ba
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7 0
3 years ago
How many positive integers less than or equal to 100 have a prime factor that is greater than 4?
Aleks [24]

Answer:

97, 89, 83, 73, 71, 67, 61, 59, 53, 47,94,43,86, 41, 82, 37,74, 31,62,93, 29,58,87, 23,46,69, 92, 19, 38,57,76,95, 17,34,51,68,85, 13,26,39,52,65,78,91, 11,22,33,44,55,66,77,88,99, 7,14,21,28,35,42,49,56,63,70,77,84,91,98,

5,10,15,20,25,30,40,45,50,60,75

Step-by-step explanation:

We have to find the  positive integers less than or equal to 100 have a prime factor that is greater than 4

First let us find out the prime factors greater than 4 and less than 100

They are

5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89 and 97.

Let us start from the highest.

Greatest is 97, next 89, 83, 73, 71, 67, 61, 59, 53, 47,94, 43,86, 41, 82, 37,74, 31,62,93, 29,58,87, 23,46,69, 92, 19, 38,57,76,95, 17,34,51,68,85, 13,26,39,52,65,78,91, 11,22,33,44,55,66,77,88,99, 7,14,21,28,35,42,49,56,63,70,77,84,91,98, 5,10,15,20....100

i.e. we consider each prime number and write its multiples also below 100

Now let us remove the repititions.

The answer would be

97, 89, 83, 73, 71, 67, 61, 59, 53, 47,94,43,86, 41, 82, 37,74, 31,62,93, 29,58,87, 23,46,69, 92, 19, 38,57,76,95, 17,34,51,68,85, 13,26,39,52,65,78,91, 11,22,33,44,55,66,77,88,99, 7,14,21,28,35,42,49,56,63,70,77,84,91,98,

5,10,15,20,25,30,40,45,50,60,75

3 0
4 years ago
What is the answer to 2/7 x 4 4/9
ololo11 [35]
To figure this out first make the 4 4/9 into a improper fraction making it 40/9 and then multiply 2/7 x 40/9 then make is a mixed fraction :) hope this helped.
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