6.
the y-intercept is 4, which means the line crosses the y-axis at the point (0,4).
[just put a dot on the number four that's right under the letter y]
the slope of the line is positive, so it goes up from left to right.
Start at the y-intercept. Move up 2 and then move right 1.
You are now at the point (1,6).
[go to 1 for the horizontal line, then go up 6 spaces.] [connect two points]
7. y= -1/2-3
8. y=3x+4
<u>We are given:</u>
The function: y = -16t² + 64
where y is the height from ground, t seconds after falling
<u>Part A:</u>
when the droplet would hit the ground, it's height from the ground will be 0
replacing that in the given function:
0 = -16t² + 64
16t² = 64 [adding 16t² on both sides]
t² = 4 [dividing both sides by 16]
t = 2 seconds [taking square root of both sides]
<u>Part B:</u>
for second droplet,
height from ground = 16 feet
time taken = t seconds
acceleration due to gravity = 10 m/s²
initial velocity = 0 m/s
h = ut + (1/2)at² [second equation of motion]
16 = (0)(t) + (1/2)(10)(t²)
16 = 5t²
t² = 16/5
t = 1.8 seconds (approx)
Therefore, the second droplet takes the least amount time to hit the ground
Answer:
F = (-2,4); E = (-2,0); D = (2,0)
Step-by-step explanation:
F = 4 points from A, so by a scale factor of 2, it would be 2 times father away from A. The same thing applies for all of the other points; just find how much father A is from a point, then dilate that point by multiplying it by the scale factor, and settling the point closer or father from A.
