(15x^(1/3))(y^(1/5))

sveticcg [70]

The answer would be x=-7

Please put me as a Brainlier

5 0

3 years ago

Pizza Paradise offers 4 types of crust, 10 toppings, and 8 kinds of cheese for the mega calzone. How many different mega calzone

Bumek [7]

Answer:

26880 ways

Step-by-step explanation:

Given

$Crust = 4$

$Toppings = 10$

$Cheese = 8$

Required

Determine the number of ways 3 toppings and 3 cheese can be selected

The number of crusts to be selected was not stated. So, I'll assume 1 crust to be selected from 4.

This can be done in $^4C_1$ ways

For the toppings:

3 can be selected from 10 in $^{10}C_3$ ways

For the cheeses:

3 can be selected from 8 in $^{8}C_3$ ways

Total number of selection is:

$Total = ^4C_1 * ^{10}C_3 * ^{8}C_3$

Apply combination formula:

$Total = \frac{4!}{(4-1)!1!} * \frac{10!}{(10-3)!3!} * \frac{8!}{(8-3)!3!}$

$Total = \frac{4!}{3!1!} * \frac{10!}{7!3!} * \frac{8!}{5!3!}$

$Total = \frac{4*3!}{3!*1} * \frac{10*9*8*7!}{7!*3*2*1} * \frac{8*7*6*5!}{5!*3*2*1}$

$Total = \frac{4}{1} * \frac{10*9*8}{3*2*1} * \frac{8*7*6}{3*2*1}$

$Total = 4 * \frac{720}{6} * \frac{336}{6}$

$Total = 4 * 120* 56$

$Total = 26880$

<em>Hence, there are 26880 ways</em>

5 0

3 years ago

Please answer, I don't know because I'm not the smartest.

Eva8 [605]

Answer:

9 * l = 54

Step-by-step explanation:

You don't need to worry because you are not the smartest, everyone are different, some concepts might be difficult, but will become easy soon....

Here is the answer to your question,

area of a rectangle = length * width

( * = multiplication symbol, specifying as many feel confused )

A = l * w

Here..... A = 54 m², w = 9m

54 = l * 9 or...

9 * l = 54

7 0

3 years ago

Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of thre

Hatshy [7]

Answer:

35 possible combinations would be there.

Step-by-step explanation:

We have total of seven students we have to choose three out of those seven

$^{n}C_r=\frac{n!}{r!\cdot (n-r)!}$

n is the total possibilities n =7 in the given case

And r is the chosen ones

Hence, r=3 in the given case.

Substituting the values of n and r in the formula we get

$^{7}C_3$

$\frac{7!}{3!(7-3)!}$

$\frac{7!}{3!\cdot 4!}$

Using n!=n(n-1)----1

$\frac{7\cdot 6\cdot 5\cdot 4!}{3\cdot 2\cdot 1\cdot 4!}$

Cancel the common factor we get

$35$ possible combinations would be there.

8 0

3 years ago

What is the median of the data set? 14, 19, 18, 12, 22, 15, 16, 16, 14, 14, 21, 20

makkiz [27]

Answer:

16

Step-by-step explanation:

3 0

3 years ago

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