Answer:
Add the equations in order to solve the first variable. Plug this value into the other equation in order to solve the remaining variables.
The point form is (3,-1)
The equation form is x = 3, y = -1
Hope this helps!
<u><em>PLEASE, </em></u>consideer brainliest. I only have 3 left and then my rank will go up.
Answer:
three (3)
Step-by-step explanation:
4x is the first term
-4 is the second term
3y is the third term
Answer:
The teacher is 1.416667 times taller than the student
Step-by-step explanation:
(5 2/3)/4
=1.416667
Answer:
26.2 units
Step-by-step explanation:
We are given the points/vertices
A(6, 3),
B(6, - 2) , and
C(- 4, 3)
Step two
Let us find the distances between the given points/vertices
A-B =A(6, 3) to B(6,-2)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6-6)²+(-2-3)²)
d=√(-2-3)²)
d=√(-5)²)
d=5 units
B-C=B(6, - 2) to C(-4, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((-4-6)²+(3+2)²)
d=√(-10)²+(5)²)
d=√100+25
d=√125
d=11.2 units
C-A=C(-4, 3) to A(6, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6+4)²+(3-3)²)
d=√(10)²
d=√100
d=10 units
Hence the perimeter is 5+11.2+10
P=26.2 units
Given:
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

To find:
The current that will produce the maximum power.
Solution:
We have,

Here, leading coefficient is negative. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
If a parabola is
, then

In the given function, a=-12 and b=120. So,



Putting x=5 in the given function, we get




Therefore, 5 watt current will produce the maximum power of 300 amperes.