Please help quickly, it would be really appreciated.

HELP ME PLEASE !!!!!!!

MaRussiya [10]

24:36
9:12
12:16
Because yes

6 0

3 years ago

Read 2 more answers

Which is the simplified form of this expression? (2x+3) (x-6)-2x^2+3x+30

docker41 [41]

-6x + 12

To find this answer, follow these steps:

First, multiply 2x + 3 and x - 6 using either the FOIL method or the box method. This should get you the answer of 2x^2 - 9x - 18

This should now replace the 2x + 3 and x - 6

So with that, you should have this currently:

2x^2 - 9x - 18 - 2x^2 + 3x + 30

Now, combine like terms:

The 2x^2 cancels each other out. After that, combine -9x and 3x to get -6x. Then -18 and 30.

This should leave you with the final answer of -6x + 12

Hope this helps!

8 0

3 years ago

Orlando bought a pair of shoes that was on sale for $30 off. The original price of the shoes was $112. What was the sale price o

d1i1m1o1n [39]

The answer is 16 can you give me brainliest ?

3 0

3 years ago

You are having a family meeting during the a epidemic. You want to follow the guidelines and know everyone has to stay 6 feet ap

Lady_Fox [76]

Answer:

a.

Total No. of People = 8 people

b.

Total No. of People = 6 people

Hence, we can not fit the same amount of people in both rooms.

Step-by-step explanation:

a.

Here, the dimensions of the room are 12 ft by 24 ft. So, in order to maintain the 6 ft distance, we can allow following number of people in it.

No. of people along 24 ft dimension = 24 ft/6 ft

No. of people along 24 ft dimension = 4

No. of rows along 12 ft dimension = 12 ft/6 ft

No. of rows along 12 ft dimension = 2

So, the total no. of people is given as:

Total No. of People = (People along 24 ft)(Rows along 12 ft)

Total No. of People = (4)(2)

Total No. of People = 8 people

b.

Here, the dimensions of the room are 16 ft by 18 ft. So, in order to maintain the 6 ft distance, we can allow following number of people in it.

No. of people along 16 ft dimension = 16 ft/6 ft

No. of people along 16 ft dimension = 2.67

In order to maintain minimum 6 ft distance the no. of people is rounded down to 2.

No. of people along 16 ft dimension = 2

No. of rows along 18 ft dimension = 18 ft/6 ft

No. of rows along 18 ft dimension = 3

So, the total no. of people is given as:

Total No. of People = (People along 24 ft)(Rows along 12 ft)

Total No. of People = (2)(3)

Total No. of People = 6 people

Hence, we can not fit the same amount of people in both rooms.

8 0

3 years ago

Read 2 more answers

The data below are the frequency of cremation burials found in 17 archaeological sites. a. Obtain the mean, median, and mode of

Sergeeva-Olga [200]

Answer:

(a) The mean of the data is 275.

(b) The median of the data is 85.

(c) The mode of the data is 45.

(d) The measure of center that works best here will be median.

Step-by-step explanation:

We are given below the frequency of cremation burials found in 17 archaeological sites. Arranging those in ascending order we get;

28, 31, 32, 45, 45, 47, 59, 67, 85, 86, 143, 256, 272, 390, 424, 524, 2141.

(a) The formula for calculating mean for the above data is given by;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{28+ 31+ 32+ 45+ 45+ 47+ 59+ 67+ 85+ 86+ 143+ 256+ 272+ 390+ 424+ 524+ 2141}{17}$

= $\frac{4675}{17}$ = 275

So, the mean of the data is 275.

(b) Since, the number of observations (n) in our data is odd (i.e. n = 17) , so the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

= $(\frac{17+1}{2} )^{th} \text{ obs.}$

= $(\frac{18}{2} )^{th} \text{ obs.}$

= $9^{th} \text{ obs.}$ = 85

So, the median of the data is 85.

(c) Mode is that value in our data which appears maximum number of times in our data.

So, after observing our data we can see that only number 45 is appearing maximum number of times (2 times) and all other numbers are appearing only once.

So, the mode of the data is 45.

(d) The measure of center that works best here will be median because there are outliers in our data (means extreme values) and mean gets affected by the outliers.

So, the best measure would be median as it represents the middle most value of our data.

4 0

3 years ago