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2 years ago

Please help quickly, it would be really appreciated.

Mathematics

1 answer:

Gekata [30.6K]2 years ago

3 0

Answer:

ASA

Step-by-step explanation:

The triangles are congruent by ASA.

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Can someone tell me if idid this right i’m confused.

Allushta [10]

No u didn’t, the line is wrong. from the point -1 it should intercept (-2,-4) and (2,2)

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3 years ago

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2. Given square CANE with diagonals

svlad2 [7]

What’s something goes up but never comes down?

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3 years ago

What is the volume of the can below? Use Pi = 3.14 and round your answer to the nearest tenth. A cylinder with height 96 millime

Serga [27]

Answer:

$328,268 mm^3$

Step-by-step explanation:

The can in this problem has a cylindrical shape. The volume of a cylinder can be calculated with the following formula:

$V=\pi r^2 h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

In this problem we have:

h = 96 mm is the height of the can

d = 66 mm is the diameter of the can

So the radius of its base is

$r=\frac{d}{2}=\frac{66}{2}=33 mm$

And therefore, the volume of the can is:

$V=\pi (33)^2 (96)=328,268 mm^3$

7 0

2 years ago

Read 2 more answers

Given P(A)=0.78P(A)=0.78, P(B)=0.65P(B)=0.65 and P(A\cup B)=0.873P(A∪B)=0.873, find the value of P(A\cap B)P(A∩B), rounding to t

Sever21 [200]

Answer:

$P(A\ n\ B) = 0.557$

Step-by-step explanation:

Given

$P(A) = 0.78$

$P(B) = 0.65$

$P(A\ u\ B) = 0.873$

Required

Determine $P(A\ n\ B)$

From laws of probability, we have:

$P(A\ n\ B) = P(A) + P(B) - P(A\ u\ B)$

Substitute in values

$P(A\ n\ B) = 0.78 + 0.65 - 0.873$

$P(A\ n\ B) = 0.557$

Hence, $P(A\ n\ B)$ <em> is calculated to be 0.557</em>

8 0

2 years ago

Write the equation of a circle whose center is at (3,-2) and has a radius of 11.<br>Show your work!

Viefleur [7K]

Answer:

$(x - 3)^{2} + (y + 2)^{2} = 121$

Step-by-step explanation:

The equation of a circle has the following format:

$(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}$

In which r is the radius and the centre is the point $(x_{0}, y_{0})$

In this question:

Center at (3,-2), so $x_{0} = 3, y_{0} = -2$

Radius 11, so $r = 11$

Then

$(x - 3)^{2} + (y - (-2))^{2} = 11^{2}$

$(x - 3)^{2} + (y + 2)^{2} = 121$

3 0

2 years ago