Answer:
P(X > 112) = 0.21186.
Step-by-step explanation:
We are given that the random variable X is normally distributed, with mean 
= 100 and standard deviation 
= 15.
Let X = <u><em>a random variable</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = 
~ N(0,1)
where, = population mean = 100
= standard deviaton = 15
Now, the probability that the random variable X is greater than 112 is given by = P(X > 112)
P(X > 112) = P( > 
) = P(Z > 0.80) = 1- P(Z 
0.80)
= 1 - 0.78814 = <u>0.21186</u>
The above probability is calculated by looking at the value of x = 0.80 in the z table which has an area of 0.78814.
Answer:
They are 12 and 9
Step-by-step explanation:
Answer:
5+2c
Step-by-step explanation:
5 stands for the 5 dollar he will get weekly, doing chores or not, and the 2c stands for for every chore(s) he does, he will get 2 extra dollar.
have a nice day
Answer:
One angle is always 90° or right angle. The side opposite angle 90° is the hypotenuse. The hypotenuse is always the longest side. The sum of the other two interior angles is equal to 90°.
Step-by-step explanation:
The <em>correct answers</em> are:
5x²+70x+245 ≥ 1050; and
Yes.
Explanation:
Let x be the width of the tablet. Since the width of the TV is 7 inches more than the tablet, the width of the TV would be x+7.
The length of the TV is 5 times the width; this makes the length 5(x+7) = 5x+35.
The area of the TV would be given by
(x+7)(5x+35).
Since Andrew wants the area to be at least 1050, we set the expression greater than or equal to 1050:
(x+7)(5x+35) ≥ 1050
Multiplying this, we have:
x*5x+x*35+7*5x+7*35 ≥ 1050
5x²+35x+35x+245 ≥ 1050
Combining like terms,
5x²+70x+245 ≥ 1050
To see if 8 is a reasonable width for the tablet, we substitute 8 for x:
5(8²)+70(8)+245 ≥ 1050
5(64)+560+245 ≥ 1050
320+560+245 ≥ 1050
1125 ≥ 1050
Since this inequality is true, 8 is a reasonable width.
