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adell [148]
3 years ago
13

Explain how you can use a model to find 6×17

Mathematics
2 answers:
ipn [44]3 years ago
7 0
The anwser is 102 I don’t know about the other part
Ivan3 years ago
3 0
It's 102 I don't how you can use a model though
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Write an expression that is equivalent to 3/4 (5z+ 16
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<span>(15/4)*z + 12?... I tried working with different ways on the calculator to get the answer and that might be it.</span>
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3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

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3 years ago
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10+20 =30 so the answer is 30 square centimeters
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3 years ago
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