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True [87]
3 years ago
11

One plane at 520 feet is ascending at a rate of 40 feet per minute. While another plane at 3800 feet is descending at a rate of

120 feet per minute. How long will take the two planes to be at the same altitude?
Mathematics
1 answer:
cluponka [151]3 years ago
5 0

It takes 20.5 minutes for the two planes to be at the same altitude.

<u>Step-by-step explanation</u>:

Let 't' be time at which the two planes be at the same altitude.

  • One plane at 520 feet is ascending at a rate of 40 feet per minute.

⇒ 520 + 40t

  • Another plane at 3800 feet is descending at a rate of 120 feet per minute.

⇒ 3800 - 120t

When two plane be at the same altitude,

⇒ 520 + 40t = 3800 - 120t  

⇒ 160t = 3280

⇒ t = 3280/160

t = 20.5 minsutes

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Step-by-step explanation:

A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

This is what i get

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First, find the <em>rate</em><em> </em><em>of change</em><em> </em>[<em>slope</em>]:

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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

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