That’s really nice man. I’m sure she’ll love it
Just add up all the sides
10 + 10 + 4 + 4 = 28
Hope that helps
Right triangles satisfy Pythagorean equation given:
c^2=a^2+b^2
where
c is the hypotenuse
a and b are the legs
thus, from the choices given, the Pythagorean triple will be:
c] 5^2+12^2=13^2
assuming the triangle is an isosceles, or namely that the two slanted sides are equal to each other, and thus the line in the middle is perpendicular to the base, so we can just use the pythagorean theorem to get the length of the slanted sides and then add them together with the base for the perimeter, Check the picture below.

so that'd be the length of one of the a slanted sides, we have two of them equal, so let's just add them up and the base.
![\cfrac{\sqrt{576x^2y^4+49x^2+42x+9}}{2}+\cfrac{\sqrt{576x^2y^4+49x^2+42x+9}}{2}+(7x+3) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\large perimeter}}{7x+3+\sqrt{576x^2y^4+49x^2+42x+9}}~\hfill](https://tex.z-dn.net/?f=%5Ccfrac%7B%5Csqrt%7B576x%5E2y%5E4%2B49x%5E2%2B42x%2B9%7D%7D%7B2%7D%2B%5Ccfrac%7B%5Csqrt%7B576x%5E2y%5E4%2B49x%5E2%2B42x%2B9%7D%7D%7B2%7D%2B%287x%2B3%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20perimeter%7D%7D%7B7x%2B3%2B%5Csqrt%7B576x%5E2y%5E4%2B49x%5E2%2B42x%2B9%7D%7D~%5Chfill)