Question

Help me on this question please

Answer 1

Because PQRS is a parallelogram, you know that $2x-1=y-1$ and $3y-11=x+4$. (This is because PT and TR are congruent, and the same goes for ST and TQ.)

Writing the equations in standard form, you have

$\begin{cases}2x-y=0\\x-3y=-15\end{cases}$

Solving this system gives $x=3$ and $y=6$. So,

$PT=TR=5$
$ST=TQ=7$