Given lines l, m and n are all parallel and cut by two transversal lines, find the value of x.
1 answer:
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Answer:
see attached
Step-by-step explanation:
The x-coordinate of the vertex is given by ...
x = -b/(2a)
for f(x) = ax^2 +bx +c.
We see that the vertex is at x = 1, and we are given a = -16. Then we can find "b" from ...
1 = -b/(2(-16))
32 = b
We know the y-intercept of the equation is 5 (the starting height), so the equation must be ...
h(t) = -16t^2 +32t +5 . . . . . matches the last choice
Answer:
sin ( 11π / 8 ) = sin ( π + 3 π/ 8 ) =
= - sin ( 3π/8 ) =
= - sin ( 3π/4 / 2 ) =
Step-by-step explanation:
