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Alexeev081 [22]
3 years ago
13

How do you factor this? 2z^2-12z+10=0

Mathematics
2 answers:
maw [93]3 years ago
7 0

2x^2-12z+10=0

Common multiple is 2.

2(z^2-6z+5)=0

Simplify inside parentheses.

2(z-5)(z-1)=0 is your answer

kotykmax [81]3 years ago
4 0

Answer:

This can't be factored right now! But if it is 2z^2+12z+10=0 than it will be factored like this:

2*(z+5)(z+1)

Step-by-step explanation:

2*(z^2+6z+5)=0

2*(z+5)(z+1)

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What additional information can be used to prove ΔDSB ≅ ΔTSR by SAS?
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Please find the attached file for a proper understanding of the question given here. The diagram in the file attached is the complete accompanying diagram of the question.

As per that diagram, RS\cong SB (which is given)

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Thus, DS\cong ST is the correct answer.


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