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alexira [117]
3 years ago
9

Help on 4 plz quick also if you can

Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

The area of the rect. is 100 ft times 64 ft, or 6400 ft^2.

Let's list factors of 6400: 64,100

64= 2^6

100= 2^2*5^2

Here we see that 2 appears 8 times as a factor, and 5 appears 2 times:

6400 = 2^6 * 10^2 = 2^8*5^2

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Restrict the domain of the quadratic function and find its inverse. Confirm the inverse relationship using composition. f(x) = 0
ANTONII [103]

The given function is

f(x)= 0.2 x²

Since f(x) will be defined for all real values of x.

So, Domain of f(x) will be ( x| x is a real number.)→This is set builder notation.

Finding the inverse of f(x):

y = 0.2 x²

→ x²= 5 y

→x = \pm\sqrt{5 y}→ → Inverse of f(x)

Replacing x by y and y by x,we get inverse of the given function

y = \pm\sqrt{5 x}→ →Domain x ≥ 0, x∈[0,∞]

Graph of function and its inverse are shown below.

8 0
3 years ago
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The diagram shows a sector of a circle radius 10 cm. the angle is 135 degrees
Black_prince [1.1K]

Answer:

The perimeter is 43.6 cm

Step-by-step explanation:

In this question, we are tasked with calculating the perimeter of the sector.

Firstly, we define what a sector is. A sector is part of a circle which is is blinded by two radii and an arc. Hence we say a sector contains two radii.

Thus, to calculate the perimeter of the sector, we need the length of the arc added to 2 * length of the radius

Let’s calculate the length of the arc.

Mathematically, this is theta/360 * 2 * pi * r

where theta is the angle subtended at the middle of the circle which is 135 according to the question, and our radius is 10cm

Thus, we have

135/360 * 2 * 22/7 * 10 = 23.57 cm

Adding two radii to this, we have;

23.57 + 2(10)

= 23.57 + 20 = 43.57 = 43.6 cm to 1 decimal place

5 0
3 years ago
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Answer:

The answer is false

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Answer:

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Please help me!? Explain why i got this wrong ? how to do it right?
IgorLugansk [536]
Y - y1 = m(x - x1)
slope(m) = -3/7
(5,8)...x1 = 5 and y1 = 8
now we sub
y - 8 = -3/7(x - 5) <===
3 0
3 years ago
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